8b^2-11=0

Solution for 8b^2-11=0 equation:

8b^2-11=0

a = 8; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·8·(-11)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{22}}{2*8}=\frac{0-4\sqrt{22}}{16}
=-\frac{4\sqrt{22}}{16}
=-\frac{\sqrt{22}}{4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{22}}{2*8}=\frac{0+4\sqrt{22}}{16}
=\frac{4\sqrt{22}}{16}
=\frac{\sqrt{22}}{4}
$